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'**********************************************************************************************************
' Name: cutChars
' Author: mielk | 2013-05-15
'
' Comment: Function cuts the specified number of characters at the end of the source string.
'
' Parameters:
' text String to be shortened.
' chars Number of characters to be cutted. It should be positive number.
' If this argument is 0 or negative number, the original string is returned without
' any changes.
'
' Returns:
' String The original string without the specified number of characters at the end of this
' string.
'
' Example:
' ?cutChars("String", 3) = "Str" <--- 3 characters have been cut from the original
' string "String")
'
'
' --- Changes log -----------------------------------------------------------------------------------------
' 2013-05-15 mielk Method created.
'**********************************************************************************************************
Public Function cutChars(text As String, chars As Integer) As String
Const METHOD_NAME As String = "cutChars"
'------------------------------------------------------------------------------------------------------
'Check if the number of characters to be cutted is not greater than the length of the base string.
'If it is, return empty String.
If chars > VBA.Len(text) Then
cutChars = ""
Else
cutChars = VBA.Left$(text, VBA.Len(text) - chars)
End If
End Function